Rcpp Version 1.0.9
Misc/ifelseLooped.r

Nice example of accelerating path-dependent loops with Rcpp

#!/usr/bin/env r
##
## This example goes back to the following StackOverflow questions:
## http://stackoverflow.com/questions/7153586/can-i-vectorize-a-calculation-which-depends-on-previous-elements
## and provides a nice example of how to accelerate path-dependent
## loops which are harder to vectorise. It lead to the following blog
## post:
## http://dirk.eddelbuettel.com/blog/2011/08/23#rcpp_for_path_dependent_loops
##
## Thanks to Josh Ulrich for provided a first nice (R-based) answer on
## StackOverflow and for also catching a small oversight in my posted answer.
##
## Dirk Eddelbuettel, 23 Aug 2011
##
## Copyrighted but of course GPL'ed
library(inline)
library(rbenchmark)
library(compiler)
fun1 <- function(z) {
for(i in 2:NROW(z)) {
z[i] <- ifelse(z[i-1]==1, 1, 0)
}
z
}
fun1c <- cmpfun(fun1)
fun2 <- function(z) {
for(i in 2:NROW(z)) {
z[i] <- if(z[i-1]==1) 1 else 0
}
z
}
fun2c <- cmpfun(fun2)
funRcpp <- cxxfunction(signature(zs="numeric"), plugin="Rcpp", body="
Rcpp::NumericVector z = Rcpp::NumericVector(zs);
int n = z.size();
for (int i=1; i<n; i++) {
z[i] = (z[i-1]==1.0 ? 1.0 : 0.0);
}
return(z);
")
z <- rep(c(1,1,0,0,0,0), 100)
## test all others against fun1 and make sure all are identical
all(sapply(list(fun2(z),fun1c(z),fun2c(z),funRcpp(z)), identical, fun1(z)))
res <- benchmark(fun1(z), fun2(z),
fun1c(z), fun2c(z),
funRcpp(z),
columns=c("test", "replications", "elapsed", "relative", "user.self", "sys.self"),
order="relative",
replications=1000)
print(res)
z <- c(1,1,0,0,0,0)
res2 <- benchmark(fun1(z), fun2(z),
fun1c(z), fun2c(z),
funRcpp(z),
columns=c("test", "replications", "elapsed", "relative", "user.self", "sys.self"),
order="relative",
replications=10000)
print(res2)
if (FALSE) { # quick test to see if Int vectors are faster: appears not
funRcppI <- cxxfunction(signature(zs="integer"), plugin="Rcpp", body="
Rcpp::IntegerVector z = Rcpp::IntegerVector(zs);
int n = z.size();
for (int i=1; i<n; i++) {
z[i] = (z[i-1]==1.0 ? 1.0 : 0.0);
}
return(z);
")
z <- rep(c(1L,1L,0L,0L,0L,0L), 100)
identical(fun1(z),fun2(z),fun1c(z),fun2c(z),funRcppI(z))
res3 <- benchmark(fun1(z), fun2(z),
fun1c(z), fun2c(z),
funRcppI(z),
columns=c("test", "replications", "elapsed", "relative", "user.self", "sys.self"),
order="relative",
replications=1000)
print(res3)
z <- c(1L,1L,0L,0L,0L,0L)
res4 <- benchmark(fun1(z), fun2(z),
fun1c(z), fun2c(z),
funRcppI(z),
columns=c("test", "replications", "elapsed", "relative", "user.self", "sys.self"),
order="relative",
replications=10000)
print(res4)
}